golang Implementation of two go procedures that take turns printing a slice
- 2020-11-20 06:08:03
- OfStack
Problem description:
Two go processes print one slice in turn.
Golang implementation:
Use two channel, just for judgment
package main
import (
"fmt"
"sync"
)
// two go Serial printing 1 A slice
func main() {
ch1 := make(chan bool, 1)
ch2 := make(chan bool, 1)
ch1 <- true
nums := []int{1, 2, 3, 4, 5, 6, 7, 8, 9}
var i int
var wg sync.WaitGroup
wg.Add(2)
go func() {
for ; i < len(nums) && <-ch1; i++ {
fmt.Println(nums[i])
ch2 <- true
}
wg.Done()
}()
go func() {
for ; <-ch2 && i < len(nums); i++ {
fmt.Println(nums[i])
ch1 <- true
}
wg.Done()
}()
wg.Wait()
}
Pay attention to
To clarify the judgment conditions of the two subES19en procedures, it is necessary to judge the size of i first or whether the pipe has value first.
A slight mistake can cause a deadlock.
Use two channel to pass values
package main
import (
"fmt"
"sync"
)
// two go Serial printing 1 A slice
func main() {
ch1 := make(chan int, 1)
ch2 := make(chan int, 1)
nums := []int{1, 2, 3, 4, 5, 6, 7, 8, 9}
ch1 <- nums[0]
i := 1
numsLen := len(nums)
var wg sync.WaitGroup
wg.Add(2)
go func() {
for ; i < numsLen; i++ {
val := <-ch1
fmt.Println(val)
ch2 <- i+1
}
wg.Done()
}()
go func() {
for ; i < numsLen; i++ {
val := <- ch2
fmt.Println(val)
ch1 <- i+1
}
wg.Done()
}()
wg.Wait()
}